AIIMS2018PhysicsElectrostatics
A uniformly charged non conducting disc with surface charge density 10 nC / m ^2 having radius 3 ~cm . Then find the magnitude of electric field at a point on the perpendicular bisector at a distance 2 ~cm from origin of the disc.
Options
- A251 ~N / C
- B126 ~N / C
- C502 ~N / C
- D72 ~N / C
Correct answer
A. 251 ~N / C
Step-by-step solution
aligned & E= 4 ₀ (2 ) [1- x R^2+x^2 ] & =9 10^9 10 10⁻⁹ 6.28 [1- 2 4+9 ] & E=90 6.28 [1- 2 13 ]=251 ~N / C aligned