Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JIPMER2018PhysicsElectrostatics

The force of attraction between two charges 8 C and -4 C is 0.2 N . Find the distance of separation

Options

  1. A1.2 m
  2. B12 m
  3. C120 m
  4. D0.12 m

Correct answer

A. 1.2 m

Step-by-step solution

Given that, F=0.2 ~N , Q ₁=8 C , Q ₂=4 C Force between two charges, F = k Q ₁ Q ₂ r ^2 or 0.2=9 10^9 8 10⁻⁶ 4 10⁻⁶ r ^2 r^2= 9 10^9 8 10⁻⁶ 4 10⁻⁶ 0.2 or r =1.2 ~m

Practice Electrostatics on Quantrex Academy →

More from Electrostatics

The electric field at a point in a certain region of free space due to a charge Q is 0. The electric potential at that point is 2026A closed surface encloses n electric dipoles. The net electric flux through the closed surface is ( ₀ = permittivity of free space, q = charge) 2026A hollow metal sphere of radius 5 cm is charged such that the potential on its surface is 10 V . The electric field at its centre is 2026Four infinitely large planar charged sheets are placed parallel to each other as shown in Figure 1. Find the magnitude of electric field at point P. 2026The electric potential 'V' as a function of distance x (in metre) is V = 4x^2 + 6x - 8 volt. Electric field at x = 2 m is 2026A uniform electric field is given as E = 4 10^4 , j N/C . The flux of this field through a square of side 10 cm whose plane is parallel to the Y-Z plane is 2026Assume that the electric field E = 30 x^2 i exists in space. Then the potential difference V_A - V_O , where ' V_O ' is the potential at the origin and ' V_A ' is the potential at 2026Two point charges +8q and -2q are located at x=0 and x=L respectively. What is the location of a point on the x-axis from the origin, at which the net electric field due to these t 2026 Full Electrostatics list All JIPMER PYQs