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AIIMS 201826 May
Exam
AIIMS
Year
2018
Date
26 May
Subject
Physics
Chapter
Motion in One Dimension

AIIMS 2018 · 26 May · Physics · Motion in One Dimension

A boy stands on a weighing machine inside a lift. When the lift is...

A boy stands on a weighing machine inside a lift. When the lift is going down with acceleration g/4g / 4, the machine shows a reading 30 kgf. When the lift goes upwards with acceleration g/4g / 4, the reading would beA boy stands on a weighing machine inside a lift. When the lift is going down with acceleration g / 4 , the machineA boy stands on a weighing machine inside a lift. When the lift is going down with acceleration g / 4 , the machine

Options

  1. A18kgf18 \mathrm{kgf}
  2. B37.5kgf37.5 \mathrm{kgf}
  3. C50kgf50 \mathrm{kgf}
  4. D67.5kgf67.5 \mathrm{kgf}

Correct answer

C. 50kgf50 \mathrm{kgf}

Step-by-step solution

While going down, machine reading is 30kgf30 \mathrm{kgf}. ⇒mg−N=m(g4)mg−30g=mg4;3mg4=30gm=30×43=40 kg\begin{aligned} & \Rightarrow m g-N=m\left(\frac{g}{4}\right) \\ & m g-30 g=\frac{m g}{4} ; 3 \frac{m g}{4}=30 g \\ & m=\frac{30 \times 4}{3}=40 \mathrm{~kg}\end{aligned} A boy stands on a weighing machine inside a lift. When the lift is going down with acceleration g / 4 , the machine
While going up, the reaction would be N′−mg=mg4N′=5mg4=54(40 kg)g⇒N′=50kgf.\begin{aligned} & N^{\prime}-m g=m \frac{g}{4} \\ & N^{\prime}=5 \frac{m g}{4}=\frac{5}{4}(40 \mathrm{~kg}) g \\ \Rightarrow \quad N^{\prime} & =50 \mathrm{kgf} .\end{aligned}A boy stands on a weighing machine inside a lift. When the lift is going down with acceleration g / 4 , the machine
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