AIIMS2008PhysicsMotion in One Dimension
The displacement time graph of a particle moving along a straight line is drawn below.
Options
- A( array c|c OP & PQ & QR - & 0 & + array )
- B( array c|c OP & PQ & QR + & 0 & + array )
- C( array c|c OP & PQ & QR + & 0 & - array )
- D( array c|c OP & PQ & QR - & 0 & - array )
Correct answer
C. ( array c|c OP & PQ & QR + & 0 & - array )
Step-by-step solution
Acceleration = d^2 x d t^2 For part O P , the acceleration is positive as the velocity is increasing. Slope is increasing. For part P Q , the acceleration is zero. Horizontal straight line shows that the velocity is zero. For part Q R , acceleration is negative. It is retarded motion. Velocity is decreasing as the slope decreases with time. Hence option (c) is correct.