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AIIMS 2011
Exam
AIIMS
Year
2011
Subject
Physics
Chapter
Motion in One Dimension

AIIMS 2011 · Physics · Motion in One Dimension

A 0.2 ~kg object at rest is subjected to a force (0.3 i -0.4 j ) N...

A 0.2 kg0.2 \mathrm{~kg} object at rest is subjected to a force (0.3i^−0.4j^)N(0.3 \hat{i}-0.4 \hat{j}) \mathrm{N}. What is the velocity after 6 s6 \mathrm{~s} ?

Options

  1. A(9i^−12j^)(9 \hat{i}-12 \hat{j})
  2. B(8i^−16j^)(8 \hat{i}-16 \hat{j})
  3. C(12i^−9j^)(12 \hat{i}-9 \hat{j})
  4. D(16i^−8j^)(16 \hat{i}-8 \hat{j})

Correct answer

A. (9i^−12j^)(9 \hat{i}-12 \hat{j})

Step-by-step solution

Here, m=0.2kg,u=0m=0.2 \mathrm{ kg}, u=0F⃗=(0.3i^−0.4j^)v⃗=?,t=6sa⃗=F⃗m=(0.3i^−0.4j^)0.2=(32i^−2j^)\begin{aligned}& \vec{F}=(0.3 \hat{i}-0.4 \hat{j}) \\ & \vec{v}=?, t=6 \mathrm{ s}\\ & \vec{a}=\frac{\vec{F}}{m}=\frac{(0.3 \hat{i}-0.4 \hat{j})}{0.2}=\left(\frac{3}{2} \hat{i}-2 \hat{j}\right) \end{aligned}$FromFrom\vec{v}=\vec{u}+\vec{a} t \vec{v}=0+\left(\frac{3}{2} \hat{i}-2 \hat{j}\right)\times6=9 \hat{i}-12 \hat{j}$
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