AIIMS2011PhysicsMotion in One Dimension
A 0.2 ~kg object at rest is subjected to a force (0.3 i -0.4 j ) N . What is the velocity after 6 ~s ?
Options
- A(9 i -12 j )
- B(8 i -16 j )
- C(12 i -9 j )
- D(16 i -8 j )
Correct answer
A. (9 i -12 j )
Step-by-step solution
Here, m=0.2 ~kg , u=0 aligned & F =(0.3 i -0.4 j ) & v =?, t=6 ~s & a = F m = (0.3 i -0.4 j ) 0.2 = ( 3 2 i -2 j ) aligned From v = u + a t v =0+ ( 3 2 i -2 j ) 6=9 i -12 j