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BITSAT 2013
Exam
BITSAT
Year
2013
Subject
Chemistry
Chapter
Chemical Equilibrium

BITSAT 2013 · Chemistry · Chemical Equilibrium

If 1.0 mole of I_ 2 is introduced into 1.0 litre flask at 1000 ~K,...

If 1.0 mole of I2I_{2} is introduced into 1.0 litre flask at 1000 K,1000 \mathrm{~K}, at equilibrium (Kc=10−6),\left(\mathrm{K}_{\mathrm{c}}=10^{-6}\right), which one is correct?If 1.0 mole of I_ 2 is introduced into 1.0 litre flask at 1000 ~K, at equilibrium (K_ c =10^ -6 ), which one is correct?

Options

  1. A\left[\mathrm{I}_{2}(\mathrm{~g})\right] \gt \left[\mathrm{I}^{-}(\mathrm{g})\right]
  2. B\left[\mathrm{I}_{2}(\mathrm{~g})\right]\lt \left[\mathrm{I}^{-}(\mathrm{g})\right]
  3. C\left[\mathrm{I}_{2}(\mathrm{~g})\right]=\left[\mathrm{I}^{-}(\mathrm{g})\right]
  4. D\left[\mathrm{I}_{2}(\mathrm{~g})\right]=\frac{1}{2}\left[\mathrm{I}^{-}(\mathrm{g})\right]

Correct answer

B. \left[\mathrm{I}_{2}(\mathrm{~g})\right]\lt \left[\mathrm{I}^{-}(\mathrm{g})\right]

Step-by-step solution

If 1.0 mole of I_ 2 is introduced into 1.0 litre flask at 1000 ~K, at equilibrium (K_ c =10^ -6 ), which one is correct?
KC=(2x)2(1−x)=10−6K_{C}=\frac{(2 x)^{2}}{(1-x)}=10^{-6} It shows that (1−x)<2x(1-x)< 2 x
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