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BITSAT 2013
Exam
BITSAT
Year
2013
Subject
Chemistry
Chapter
Chemical Equilibrium

BITSAT 2013 · Chemistry · Chemical Equilibrium

For the reaction CO(g)+(1 / 2) O_ 2 ( g) CO_ 2 ( g), K_ p / K_ c is

For the reaction CO(g)+(1/2)O2(g)⟶CO2(g),Kp/Kc\mathrm{CO}(\mathrm{g})+(1 / 2) \mathrm{O}_{2}(\mathrm{ g}) \longrightarrow \mathrm{CO}_{2}(\mathrm{ g}), \mathrm{K}_{\mathrm{p}} / \mathrm{K}_{\mathrm{c}} is

Options

  1. ART\mathrm{RT}
  2. B(RT)−1(\mathrm{RT})^{-1}
  3. C(RT)−1/2(\mathrm{RT})^{-1 / 2}
  4. D(RT)1/2(\mathrm{RT})^{1 / 2}

Correct answer

C. (RT)−1/2(\mathrm{RT})^{-1 / 2}

Step-by-step solution

Kp=Kc(RT)Δn,Δn=1−(1+12)=1−32=−12∴KpKc=(RT)−1/2\mathrm{K}_{\mathrm{p}}=\mathrm{K}_{\mathrm{c}}(\mathrm{RT})^{\Delta n},\Delta \mathrm{n}=1-\left(1+\frac{1}{2}\right)=1-\frac{3}{2}=-\frac{1}{2}\therefore \frac{\mathrm{K}_{\mathrm{p}}}{\mathrm{K}_{\mathrm{c}}}=(\mathrm{RT})^{-1 / 2}
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