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BITSAT2021ChemistryChemical KineticsActual

XmL of H ₂ gas effuses through a hole in a container in 5 seconds. The time taken for the effusion of the same volume of the gas specified below under identical conditions is :

Options

  1. A10 seconds : He
  2. B20 seconds: O ₂
  3. C25 seconds: CO
  4. D55 seconds : CO ₂

Correct answer

B. 20 seconds: O ₂

Step-by-step solution

Under identical conditions, r₁ r₂ = M ₂ M ₁ As rate of diffusion is also inversely proportional to time, we will have, t₂ t₁ = M ₂ M ₁ (A) Thus, For He , t₂= 4 2 (5 s)=5 2 s 10 s ; (B) For O ₂, t₂= 32 2 (5 s)=20 s (C) For CO , t₂= 28 2 (5 s) 25 s ; (D) For CO ₂, t₂= 44 2 (5 s) 55 s #

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