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BITSAT 2018
Exam
BITSAT
Year
2018
Subject
Chemistry
Chapter
Chemical Kinetics

BITSAT 2018 · Chemistry · Chemical Kinetics

Which of the following expression is correct for the rate of...

Which of the following expression is correct for the rate of reaction given below ?

5Br−(aq)+BrO3−(aq)+6H+(aq)⟶3Br2(aq)5{Br}^{-} \left(aq\right) + {BrO}_{3}^{-} \left(aq\right) + 6H^{+} \left(aq\right) ⟶ 3{Br}_{2}\left(aq\right)+ 3H2O(l)3{H}_{2}O \left(l\right)

Options

  1. A\dfrac{\Delta\left[{\text{ Br }}^{-}\right]}{Δt} = \dfrac{5}{6}\dfrac{\Delta\left[H^{+}\right]}{Δt}
  2. B\dfrac{\Delta\left[{\text{ Br }}^{-}\right]}{Δt} = \dfrac{6}{5}\dfrac{\Delta\left[H^{+}\right]}{Δt}
  3. C\dfrac{\Delta\left[{\text{ Br }}^{-}\right]}{Δt} = \dfrac{5\Delta\left[H^{+}\right]}{Δt}
  4. D\dfrac{\Delta\left[{\text{ Br }}^{-}\right]}{Δt} = \dfrac{6\Delta\left[H^{+}\right]}{Δt}

Correct answer

A. \dfrac{\Delta\left[{\text{ Br }}^{-}\right]}{Δt} = \dfrac{5}{6}\dfrac{\Delta\left[H^{+}\right]}{Δt}

Step-by-step solution

The given chemical reaction is

5Br−(aq)+BrO3−(aq)+6H+(aq)⟶3Br2(aq)+3H2O(l)5{Br}^{-}\left(aq\right) + {BrO}_{3}^{-} \left(aq\right) + 6H^{+} \left(aq\right) ⟶ 3{Br}_{2}\left(aq\right) + 3{H}_{2}O\left(l\right)

Rate law expression for the given reaction can be written as

−15Δ[Br−]Δt=−Δ[BrO3−]Δt- \dfrac{1}{5}\dfrac{\Delta\left[{Br}^{-}\right]}{Δt} = - \dfrac{\Delta\left[{BrO}_{3}^{-}\right]}{Δt}

−16Δ[H+]Δt=+13Δ[Br2]Δt- \dfrac{1}{6}\dfrac{\Delta\left[H^{+}\right]}{Δt} = + \dfrac{1}{3}\dfrac{\Delta\left[{Br}_{2}\right]}{Δt}

⇒−Δ[Br−]Δt=−5Δ[BrO3−]Δt=−56Δ[H+]Δt⇒ - \dfrac{\Delta\left[{Br}^{-}\right]}{Δt} = - \dfrac{5\Delta\left[{BrO}_{3}^{-}\right]}{Δt} = - \dfrac{5}{6}\dfrac{\Delta\left[H^{+}\right]}{Δt}

Δ[Br−]Δt=56Δ[H+]Δt\dfrac{\Delta\left[{Br}^{-}\right]}{Δt} = \dfrac{5}{6}\dfrac{\Delta\left[H^{+}\right]}{Δt}

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