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BITSAT 2013
Exam
BITSAT
Year
2013
Subject
Chemistry
Chapter
Chemical Kinetics

BITSAT 2013 · Chemistry · Chemical Kinetics

Velocity constant of a reaction at 290 K was found to be 3.2 × 10^...

Velocity constant of a reaction at 290K290 \mathrm{ K} was found to be 3.2×10−33.2 \times 10^{-3}. At 300K300 \mathrm{ K} it will be

Options

  1. A1.28×10−21.28 \times 10^{-2}
  2. B9.6×10−39.6 \times 10^{-3}
  3. C6.4×10−36.4 \times 10^{-3}
  4. D3.2×10−43.2 \times 10^{-4}

Correct answer

C. 6.4×10−36.4 \times 10^{-3}

Step-by-step solution

The velocity constant doubles for every 10∘C10^{{}^{\circ}} \mathrm{C} rise in temperature.
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