BITSAT2009ChemistryChemical KineticsActual
The chemical reaction 2 O ₃ 3 O ₂ proceeds as follows: rate law expression should be:
Options
- Ar = k [ O ₃ ]²
- Br = k [ O ₃ ]² [ O ₂ ]⁻¹
- Cr = k [ O ₃ ]² [ O ₂ ]²
- Dr = k [ O ₃ ] [ O ₂ ]²
Correct answer
B. r = k [ O ₃ ]² [ O ₂ ]⁻¹
Step-by-step solution
O ₃ Fast O ₂+ O array l O + O ₃ Slow 2 O ₂ k = [ O ₂ ][ O ] [ O ₃ ] Rate = k ^ [ O ₃ ][ O ] array put [O] from (ii) r = k ^ [ O ₃ ] k [ O ₃ ] [ O ₂ ] = k [ O ₃ ]² [ O ₂ ]⁻¹ Note: Intermediates are never represented in rate law equation.