BITSAT 2020
- Exam
- BITSAT
- Year
- 2020
- Subject
- Chemistry
- Chapter
- Coordination Compounds
BITSAT 2020 · Chemistry · Coordination Compounds
The d -electron configurations of Cr^ 2+ , Mn^ 2+ , Fe^ 2+ and Co^...
The -electron configurations of and are and respectively. Which one of the following will exhibit the lowest paramagnetic behaviour? (Atomic no. 
Options
- A\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}
- B\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}
- C\left[\mathrm{Mn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}
- D\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}
Correct answer
A. \left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}
Step-by-step solution
Since has lowest no. of unpaired electrons hence lowest paramagnetic behaviour is shown by \left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}