For the octahedral complex, which of the following d -electron configuration will give maximum value of CFSE

Step-by-step solution

Δ 0 = - 0 . 4 × nt 2 g + 0 . 6 × ne g where, n = number of electrons in nt 2 g and ne g . CFSE of given α -electrons configuration are as follows a. For high spin, d 6 ; Δ 0 CFSE = - 0 . 4 × 4 + 0 . 6 × 2 = - 0 . 4 b. For low spin, d 4 ; Δ 0 CFSE = - 0 . 4 × 4 + 0 . 6 × 0 = 1 . 6 c. For low spin d 5 Δ 0 CFSE = - 0 . 4 × 5 + 0 . 6 × 0 = - 2 . 0 d. For high spin, d 7 Δ 0 CFSE = - 0 . 4 × 5 + 0 . 6 × 2 = - 0 . 8 Neglecting - ve sign (as it