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BITSAT2013ChemistryCoordination CompoundsActual

The pair in which both species have same magnetic moment (spin onlyvalue) is:

Options

  1. A[ Cr ( H ₂ O )₆ ]²⁺, [ CoCI ₄ ]²⁻
  2. B[ Cr ( H ₂ O ₆ )²⁺, [ Fe ( H ₂ O )₆ ]³⁺ .
  3. C[ Mn ( H ₂ O )₆ )²⁺, [ Cr ( H ₂ O )₆ ]²⁺
  4. D[ CoCl ₄ )²⁻, [ Fe ( H ₂ O )₆ ]²⁺

Correct answer

B. [ Cr ( H ₂ O ₆ )²⁺, [ Fe ( H ₂ O )₆ ]³⁺ .

Step-by-step solution

[ Cr ( H ₂ O )₆ ]²⁺ Cr is in Cr ²⁺ form In [ Fe ( H ₂ O ) ]²⁺ Fe ²⁺ form. Both will have 4 unpaired electrons.

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