BITSAT2012ChemistryCoordination CompoundsActual
Among the following the lowest degree of paramagnetism per mole of the compound at 298 K will be shown by
Options
- AMnSO ₄ 4 H ₂ O
- BCuSO ₄ .5 H ₂ O
- CFeSO ₄ 6 H ₂ O
- DNiSO ₄ 6 H ₂ O
Correct answer
B. CuSO ₄ .5 H ₂ O
Step-by-step solution
array lllll Ion & Mn ²⁺ & Cu ²⁺ & Fe ²⁺ & Ni ²⁺ EC & 3 d⁵ & 3 d⁹ & 3 d⁶ & 3 d⁸ Number of & 5 & 1 & 4 & 2 array unpaired electron Hence lowest paramagnetism is shown by CuSO ₄ 5 H ₂ O