Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
BITSAT 2012
Exam
BITSAT
Year
2012
Subject
Chemistry
Chapter
Coordination Compounds

BITSAT 2012 · Chemistry · Coordination Compounds

Among the following the lowest degree of paramagnetism per mole of...

Among the following the lowest degree of paramagnetism per mole of the compound at 298 K\mathrm{K} will be shown by

Options

  1. AMnSO4⋅4H2O\mathrm{MnSO}_{4} \cdot 4 \mathrm{H}_{2} \mathrm{O}
  2. BCuSO4.5H2O\mathrm{CuSO}_{4}.5 \mathrm{H}_{2} \mathrm{O}
  3. CFeSO4⋅6H2O\mathrm{FeSO}_{4} \cdot 6 \mathrm{H}_{2} \mathrm{O}
  4. DNiSO4⋅6H2O\mathrm{NiSO}_{4} \cdot 6 \mathrm{H}_{2} \mathrm{O}

Correct answer

B. CuSO4.5H2O\mathrm{CuSO}_{4}.5 \mathrm{H}_{2} \mathrm{O}

Step-by-step solution

$\begin{array}{lllll}\text{ Ion } & \mathrm{Mn}^{2+} & \mathrm{Cu}^{2+} & \mathrm{Fe}^{2+} & \mathrm{Ni}^{2+} \\ \text{ EC } & 3 d^{5} & 3 d^{9} & 3 d^{6} & 3 d^{8} \\ \text{ Number of } & 5 & 1 & 4 & 2\end{array} unpaired electron Hence lowest paramagnetism is shown by \mathrm{CuSO}_{4} \cdot5 \mathrm{H}_{2} O\mathrm{O}$
Practice Coordination Compounds on Quantrex Academy →

More from Coordination Compounds

Hybridisation and geometry of [Ni(CN)_4]^ 2- are BITSAT 2024Match List I with List II. List I(Complex)List II(Oxidationnumber of… BITSAT 2024Which of the following is correct order of ligand field strength? BITSAT 2024The correct statement among the following is; BITSAT 2024The type of isomerism present in nitropentammine chromium (III) chloride is BITSAT 2024Identify, from the following, the diamagnetic, tetrahedral complex BITSAT 2024The chemical name of calgon is BITSAT 2024The complex with highest magnitude of crystal field splitting energy (Δ_0) is BITSAT 2024 Full Coordination Compounds list All BITSAT PYQs