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BITSAT 2013
Exam
BITSAT
Year
2013
Subject
Chemistry
Chapter
Electrochemistry

BITSAT 2013 · Chemistry · Electrochemistry

A current of 2.0 A passed for 5 hours through a molten metal salt...

A current of 2.0 A passed for 5 hours through a molten metal salt deposits 22.2g22.2 \mathrm{ g} of metal (At wt. =177=177 ). The oxidation state of the metal in the metal salt is

Options

  1. A1
  2. B2
  3. C3
  4. D4

Correct answer

C. 3

Step-by-step solution

m=E⋅wt×Q96500\mathrm{m}=\frac{\mathrm{E} \cdot \mathrm{wt} \times \mathrm{Q}}{96500}∴E.wt=m×96500Q=22.2×965002×5×60×60=60.3\begin{aligned} \therefore \mathrm{E}. \mathrm{wt} &=\frac{\mathrm{m} \times 96500}{\mathrm{Q}} \\=\frac{22.2 \times 96500}{2 \times 5 \times 60 \times 60}=60.3 \end{aligned}$OxidationstateOxidation state=\frac{\text{ At wt. }}{\text{ Eq. wt. }}=\frac{177}{60.3}=3$
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