Al (at. wt 27 ) crystallizes in the cubic system with a cell edge of 4.05 Ã… . Its density is 2.7 g per cm^ 3 . Determine the unit cell type calculate the radius of the Al atom

Correct answer: D. fcc, 1.432 Ã = Z × M N_ 0 × a^ 3 , 2.7= Z × 27 6.02 × 10^ 23 ×(4.05)^ 3 × 10^ -24 Z=4 Hence it is face centred cubic unit lattice. Again 4 r=a 2 =5.727 Ã… r=1.432 Ã…

BITSAT 2016

Exam: BITSAT
Year: 2016
Subject: Chemistry
Chapter: Solid State

BITSAT 2016 · Chemistry · Solid State

Al (at. wt 27 ) crystallizes in the cubic system with a cell edge...

\mathrm{Al}

(at. wt 27 ) crystallizes in the cubic system with a cell edge of

4.05 Ã…

. Its density is

2.7 \mathrm{ g}

per

\mathrm{cm}^{3}

. Determine the unit cell type calculate the radius of the

\mathrm{Al}

atom

Options

A $\mathrm{fcc}, 2.432 Ã$
Bbcc, $2.432 Ã$
Cbcc, $1.432 Ã$
D $\mathrm{fcc}, 1.432 Ã$

Correct answer

D. $\mathrm{fcc}, 1.432 Ã$

Step-by-step solution

\rho=\frac{Z \times M}{N_{0} \times a^{3}}

, 2.7=

\frac{Z \times 27}{6.02 \times 10^{23} \times(4.05)^{3} \times 10^{-24}}\therefore Z=4

Hence it is face centred cubic unit lattice. Again

4 r=a \sqrt{2}=5.727 Ã…\therefore \mathrm{r}=1.432 Ã…

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