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BITSAT 2014
Exam
BITSAT
Year
2014
Subject
Chemistry
Chapter
Solid State

BITSAT 2014 · Chemistry · Solid State

An elemental crystal has a density of 8570 kg / ^ 3 . The packing...

An elemental crystal has a density of 8570kg/\mathrmm38570 \mathrm{ kg} / \mathrmm^{3}. The packing efficiency is 0.68. The closest distance of approach between neighbouring atom is 2.86A~…2.86 Ã…. What is the mass of one atom approximately?

Options

  1. A93amu93 \mathrm{amu}
  2. B39amu39 \mathrm{amu}
  3. C63amu63 \mathrm{amu}
  4. D29amu29 \mathrm{amu}

Correct answer

A. 93amu93 \mathrm{amu}

Step-by-step solution

The packing efficiency =0.68=0.68, means the given lattice is BCC\mathrm{BCC}. The closest distance of approach =2r=2 \mathrm{r}2r=2.86A=a3 or a =2×2.863=3.30A~…\begin{array}{l}2 r=2.86 A=a \sqrt{3}\\ \text{ or a }=\frac{2 \times 2.86}{\sqrt{3}}=3.30 Ã… \end{array}Let atomic weight of the element $=\mathrm{a}\begin{aligned} \therefore \frac{2 \times 9}{36 \times 10^{23} \times(3.3)^{3} \times 10^{-24}}=8.57 \\ \mathrm{a}&=8.57 \times3 \times(3.3)^{3} \times0.1 \\ \text{ and } =92.39 \simeq 93 \mathrm{amu} \end{aligned}$$$
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