In the reaction of KMnO ₄ with an oxalate in acidic medium, MnO ₄⁻ is reduced to Mn ²⁺ and C ₂ O ₄²⁻ is oxidised to CO ₂ . Hence, 50 ~mL of 0.02 M KMnO ₄ is equivalent to

Step-by-step solution

eg. of ( KMnO ₄ ) ( aligned &=5 0.02 50 &=250 0.02 &=509 . aligned ) eq. of ( KAnO ₄ eq ₁ ) of ( C ₂ O ₄ ₂- ) ( aligned 5= option 2 &=50 0.05 2 &=589 . aligned )