If the photon of wavelength 150 pm strikes an atom and one of its inner bound electron is ejected out with a velocity of 1 . 5 × 10 7 m / s , what is the energy with which it is bound to the nucleus?

Step-by-step solution

Total energy E of any photon is given by the relation : E = hc λ Where, h = Planck's constant = 6 . 6 × 10 - 34   Js c = Velocity of light = 3 × 10 8   m / s λ = wavelength = 1 . 5 × 10 - 10   m , i.e, 150   pm Thus, E = hc λ = 6 . 6 × 10 - 34 × 3 × 10 8 1 . 5 × 10 - 10 ;   E = 1 . 32 × 10 - 15   J and, energy of ejected electron E ' E ' = 1 2 mv 2 , where, m = mass of electron = 9 . 1 × 10 - 31   kg v = veloc