BITSAT2018ChemistryStructure of AtomActual
If 0 . 53 × 10 - 10 4 metre is the radius of smallest electron orbit in hydrogen like atom, then the atom is
Options
- Ahydrogen atom
- BHe +
- CLi 2 +
- DBe 3 +
Correct answer
D. Be 3 +
Step-by-step solution
For hydrogen like atom, the radius of n th orbit is given by, r n = n 2 Z r 0 Where, r 0 = 0 . 53 × 10 - 10   m and r n = 0 . 53 × 10 - 10   m 4 At ground state, n = 1 Hence, the atom is Be 3 + [ ∵ Z = 4 ] So, the atom is triply ionised beryllium Be 3 + .