In an atom, an electron is moving with a speed of 600m / s with an...

Given that velocity of electron, $v = 600m / s$

\left(\Delta x\right) . \left(m \Delta v\right) = \dfrac{h}{4\pi}$</p><p>$∆ v = 0 . 005 %~or&600ms^{- 1}$</p><p>$= \dfrac{600 \times 0 . 005}{100} = 0 . 03$</p><p>$∆ x \times 9 . 1 \times {10}^{- 31} \times 0 . 03 = \dfrac{6 . 6 \times {10}^{- 34}}{4 \times 3 . 14}$</p><p>Hence,~$∆ x = \dfrac{6 . 6 \times {10}^{- 34}}{4 \times 3 . 14 \times 0 . 03 \times 9 . 1 \times {10}^{- 31}}$</p><p>$= 1 . 92 \times {10}^{- 3}m$