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BITSAT 2013
Exam
BITSAT
Year
2013
Subject
Chemistry
Chapter
Structure of Atom

BITSAT 2013 · Chemistry · Structure of Atom

The Bohr orbit radius for the hydrogen atom (n=1) is approximately...

The Bohr orbit radius for the hydrogen atom (n=1)(n=1) is approximately 0.530A~0.530 Ã. The radius for the first excited state (n=2)(n=2) orbit is (in⁡A~)(\operatorname{in} Ã)

Options

  1. A0.13
  2. B1.06
  3. C4.77
  4. D2.12

Correct answer

D. 2.12

Step-by-step solution

Radius of hydrogen atom =0.530A~…=0.530 Ã…, Number of excited state (n)=2(n)=2 and atomic number of hydrogen atom (Z)=1(Z)=1. We know that the Bohr radius. (r)=n2Z× Radius of atom =(2)21×0.530\frac{n^{2}}{Z} \times \text{ Radius of atom }=\frac{(2)^{2}}{1} \times0.530=4 \times 0.530=2.12 Ã…
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