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BITSAT 2012

Exam: BITSAT
Year: 2012
Subject: Chemistry
Chapter: Structure of Atom

BITSAT 2012 · Chemistry · Structure of Atom

If the radius of H is 0.53 Ã… , then what will be the radius of _ 3...

If the radius of

\mathrm{H}

is

0.53 Ã…

, then what will be the radius of

{ }_{3} \mathrm{Li}^{2+}

?

Options

A $0.17 Ã…$
B $0.36 Ã…$
C $0.53 Ã…$
D $0.59 Ã…$

Correct answer

A. $0.17 Ã…$

Step-by-step solution

Radius of orbit

=\frac{\mathrmn^{2} \mathrm{a}_{\mathrm{o}}}{\mathrm{z}} \left(\mathrm{a}_{\mathrm{o}}=0.529 \mathrm{ A}\right) Radius of \mathrm{H}=\frac{(1)^{2} \times 0.529 \mathrm{ A}}{1}=0.53 \mathrm{ A} Thus, the radius of

{ }_{3}

\mathrm{Li}^{2+} will be =\frac{(1)^{2} \times 0.529}{3}=0.17 Ã…

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