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BITSAT 2024Paper 2
Exam
BITSAT
Year
2024
Paper
Paper 2
Subject
Chemistry
Chapter
Thermodynamics (C)

BITSAT 2024 · Paper 2 · Chemistry · Thermodynamics (C)

Which of the following relation is not correct?

Which of the following relation is not correct?

Options

  1. AΔH=ΔU−PΔV\Delta \mathrm{H}=\Delta \mathrm{U}-\mathrm{P} \Delta \mathrm{V}
  2. BΔ\Delta\mathrm{U}=\mathrm{q}+W+\mathrm{W}
  3. CΔSsvs+ΔSsurr≥0\Delta \mathrm{S}_{\mathrm{svs}}+\Delta \mathrm{S}_{\mathrm{surr}} \geq 0
  4. DΔG=ΔH−TΔS\Delta G=\Delta H-T \Delta S

Correct answer

A. ΔH=ΔU−PΔV\Delta \mathrm{H}=\Delta \mathrm{U}-\mathrm{P} \Delta \mathrm{V}

Step-by-step solution

H=U+PV\mathrm{H}=\mathrm{U}+\mathrm{PV} (By definition) ΔH=ΔU+Δ(PV)\Delta \mathrm{H}=\Delta \mathrm{U}+\Delta(\mathrm{PV}) at constant pressure ΔH=ΔU+PΔV\Delta H=\Delta U+P \Delta V
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