BITSAT2024ChemistryThermodynamics (C)Actual
The combustion of benzene (L) gives CO ₂( ~g ) and H ₂ O (L) . Given that heat of combustion of benzene at constant volume is -3263.9 ~kJ ~mol ⁻ ^1 at 25^ C ; heat of combustion (in kJ mol ⁻¹ ) of benzene at constant pressure will be : (R=8.314 JK ⁻¹ ~mol ⁻¹ )
Options
- A4152.6
- B452.46
- C3260
- D-3267.6
Correct answer
D. -3267.6
Step-by-step solution
C ₆ H ₆( I )+ 15 2 O ₂( ~g ) 6 CO ₂( ~g )+3 H ₂ O ( l ) n_g=6- 15 2 =- 3 2 H= U+ n_ g R T=-3263.9+ (- 3 2 ) 8.314 10⁻³ 298=-3263.9+(-3.71)=-3267.6 ~kJ ~mol ⁻¹