BITSAT2022ChemistryThermodynamics (C)Actual
Standard entropy of X₂, Y₂ and X Y₂ are 60,40 and 50 JK ⁻¹ ~mol ⁻¹ , respectively. For the reaction, 1 2 X₂+ 3 2 Y₂ X Y₃, H=-30 ~kJ , to be at equilibrium, the temperature will be
Options
- A1250 ~K
- B500 ~K
- C750 ~K
- D1000 ~K
Correct answer
C. 750 ~K
Step-by-step solution
S=S (X Y₃ )- 1 2 S (X₂ )- 3 2 S (Y₂ )=50-30-60=-40 ~J ~mol ⁻¹ ~K ⁻¹ H=-30 ~kJ =-3000 ~J G= H-T S At equilibrium, G=0T= H S = -3000 -40 =750 ~K