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BITSAT 2014
Exam
BITSAT
Year
2014
Subject
Chemistry
Chapter
Thermodynamics (C)

BITSAT 2014 · Chemistry · Thermodynamics (C)

The enthalpy of sublimation of aluminium is 330 kJ / mol . Its Ist,...

The enthalpy of sublimation of aluminium is 330 kJ/mol\mathrm{kJ} / \mathrm{mol}. Its Ist, II nd ^{\text{nd }} and III rd ^{\text{rd }} ionization enthalpies are 580,1820 and 2740 kJ2740 \mathrm{~kJ} respectively. How much heat has too be supplied (in kJ\mathrm{kJ} ) to convert 13.5 g13.5 \mathrm{~g} of aluminium into Al3+\mathrm{Al}^{3+} ions and electrons at 298k298 \mathrm{k}

Options

  1. A5470
  2. B2735
  3. C4105
  4. D3765

Correct answer

B. 2735

Step-by-step solution

Heat needed too be supplied  per \text{ per } m o l=330+580+1820+2740 =5470=5470kJ\mathrm{ kJ}No.ofmolsofAltaken=13.527=No. of mols of Al taken =\frac{13.5}{27}=0.5 mol\mathrm{ mol} Heat required =0.5×5470kJ=2735=0.5 \times 5470 \mathrm{ kJ}=2735kJ\mathrm{ kJ}
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