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BITSAT2013ChemistryThermodynamics (C)Actual

The enthalpy of combustion of 2 moles of benzene at 27^ C differs from the value determined in bomb calorimeter by

Options

  1. A-2.494 ~kJ
  2. B2.494 ~kJ
  3. C-7.483 ~kJ
  4. D7.483 ~kJ

Correct answer

C. -7.483 ~kJ

Step-by-step solution

By bomb calorimeter we get E . array l 2 C ₆ H ₆( l )+15 O ₂( ~g ) 12 CO ₂( ~g )+6 H ₂ O (1) H - E = nRT =(12-15) 8.314 300=-7.483 ~kJ array

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