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AIIMS 201926 May
Exam
AIIMS
Year
2019
Date
26 May
Subject
Physics
Chapter
Rotational Motion

AIIMS 2019 · 26 May · Physics · Rotational Motion

Given v_ C M =2 ~m ~s^ -1 , m=2 ~kg, R=4 ~m Find the angular...

Given vCM=2 m s−1v_{C M}=2 \mathrm{~m} \mathrm{~s}^{-1}, m=2 kg,R=4 mm=2 \mathrm{~kg}, R=4 \mathrm{~m} Find the angular momentum of ring about its origin if it is in pure rolling. Given v_ C M =2 ~m ~s^ -1 , m=2 ~kg, R=4 ~m Find the angular momentum of ring about its origin if it is in pure rolling.

Options

  1. A32 kg m2 s−132 \mathrm{~kg} \mathrm{~m}^2 \mathrm{~s}^{-1}
  2. B24 kg m2 s−124 \mathrm{~kg} \mathrm{~m}^2 \mathrm{~s}^{-1}
  3. C16 kg m2 s−116 \mathrm{~kg} \mathrm{~m}^2 \mathrm{~s}^{-1}
  4. D8 kg m2 s−18 \mathrm{~kg} \mathrm{~m}^2 \mathrm{~s}^{-1}

Correct answer

A. 32 kg m2 s−132 \mathrm{~kg} \mathrm{~m}^2 \mathrm{~s}^{-1}

Step-by-step solution

 L⃗=ICM⋅ω+mvCMRω=vR=24=0.5rads−1L⃗=mR2⋅ω+mvCM⋅R=2×16×0.5+2×2×4=16+16L⃗=32kgm2s−1\begin{aligned} & \text{ } \vec{L}=I_{C M} \cdot \omega+m v_{C M} R \\ & \omega=\frac{v}{R}=\frac{2}{4}=0.5 \mathrm{rad} \mathrm{s}^{-1} \\ & \vec{L}=m R^2 \cdot \omega+m v_{C M} \cdot R \\ & =2 \times 16 \times 0.5+2 \times 2 \times 4=16+16 \\ & \vec{L}=32 \mathrm{ kg} \mathrm{ m}^2 \mathrm{ s}^{-1}\end{aligned}
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