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BITSAT 2013
Exam
BITSAT
Year
2013
Subject
Mathematics
Chapter
Area Under Curves

BITSAT 2013 · Mathematics · Area Under Curves

Area intercepted by the curves y= xx ∈[0, π] and y= 2 x, x ∈[0, π],...

Area intercepted by the curves y=cos⁡xx∈[0,π]y=\cos x\mathrm{x} \in[0, \pi] and y=cos⁡2x,x∈[0,π],\mathrm{y}=\cos 2 \mathrm{x}, \mathrm{x} \in[0, \pi], is

Options

  1. A3π2\frac{3 \pi}{2}
  2. B332\frac{3 \sqrt{3}}{2}
  3. C3π4\frac{3 \pi}{4}
  4. D334\frac{3 \sqrt{3}}{4}

Correct answer

D. 334\frac{3 \sqrt{3}}{4}

Step-by-step solution

 Area =∫02π/3(cos⁡\text{ Area }=\int_{0}^{2 \pi / 3}(\cos x-\cos 2 x) d x=334\frac{3 \sqrt{3}}{4}
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