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BITSAT 2012
Exam
BITSAT
Year
2012
Subject
Mathematics
Chapter
Area Under Curves

BITSAT 2012 · Mathematics · Area Under Curves

The area bounded by the curve y= x, x -axis and the ordinates x=0...

The area bounded by the curve y=sin⁡x,xy=\sin x, x -axis and the ordinates x=0x=0 and x=π/2x=\pi / 2 is

Options

  1. Aπ\pi
  2. Bπ/2\pi / 2
  3. C1
  4. D2

Correct answer

C. 1

Step-by-step solution

Area =∫0π/2ydx=∫0π/2sin⁡xdx=[−cos⁡x]0π/2=1=\int_{0}^{\pi / 2} \mathrm{y} \mathrm{dx}=\int_{0}^{\pi / 2} \sin \mathrm{x} \mathrm{dx}=[-\cos \mathrm{x}]_{0}^{\pi / 2}=1
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