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BITSAT 2024Paper 1
Exam
BITSAT
Year
2024
Paper
Paper 1
Subject
Mathematics
Chapter
Binomial Theorem

BITSAT 2024 · Paper 1 · Mathematics · Binomial Theorem

If the 17^ th and the 18^ th terms in the expansion of (2+a)^ 50...

If the 17th 17^{\text{th }} and the 18th 18^{\text{th }} terms in the expansion of (2+a)50(2+a)^{50} are equal, then the coefficient of x35x^{35} in the expansion of (a+x)−2(a+x)^{-2} is

Options

  1. A−35-35
  2. B33
  3. C3636
  4. D−36-36

Correct answer

D. −36-36

Step-by-step solution

Given, 17th 17^{\text{th }} and 18th 18^{\text{th }} terms in the expansion (2+a)50(2+a)^{50} are equal ∴T17=T18⇒(5016)(2)34(a)16=(5017)(2)33(a)17⇒a=(5016)(5017)×2=1∴\therefore T_{17}=T_{18}\Rightarrow\binom{50}{16}(2)^{34}(a)^{16}=\binom{50}{17}(2)^{33}(a)^{17}\Rightarrow a=\frac{\binom{50}{16}}{\binom{50}{17}} \times 2=1\therefore Now, coefficient of x35x^{35} in the expansion (1+x)−2=−36∵(1+x)^{-2}=-36\because Coefficient of xrx^r is (r+1)(r+1) in (1−x)−2(1-x)^{-2}.
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