BITSAT2022MathematicsCircleActual
The locus of the mid-point of the chord if contact of tangents drawn from points lying on the straight line 4 x-5 y=20 to the circle x^2+y^2=9 is
Options
- A20 (x^2+y^2 )-36 x+45 y=0
- B20 (x^2+y^2 )+36 x-45 y=0
- C36 (x^2+y^2 )-20 x+45 y=0
- D36 (x^2+y^2 )+20 x-45 y=0
Correct answer
A. 20 (x^2+y^2 )-36 x+45 y=0
Step-by-step solution
Let P (t, 4 t-20 5 ) be a point on the line 4 x-5 y=20 . Then the chord of contact of tangents drawn from P to the circle x^2+y^2=9 is t x+ ( 4 t-20 5 ) y=9 (i) Let (h, k) be the mid-point of this chord of contact, then its equation is also h x+k y=h^2+k^2 (ii) [ . using .T=S^ ] Clearly Eqs. (i) and (ii) represent the same line aligned & t h = 4 t-20 5 k = 9 h^2+k^2 & t h = 9 h^2+k^2 and t h = 4 t-20 5 k & t= 9 h h^2+k^2 and t= 20 h 4 h-5 k & 9 h h^2+k^2 = 20 h 4 h-5 k & h 20 (h^2+k^2 )-36 h+45 k =0 & x=0, or [20 (