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BITSAT 2023Paper 2
Exam
BITSAT
Year
2023
Paper
Paper 2
Subject
Mathematics
Chapter
Circle

BITSAT 2023 · Paper 2 · Mathematics · Circle

The equation of the circle with centre (0,2) and radius 2 is...

The equation of the circle with centre (0,2)(0,2) and radius 2 is x2+y2−my=0x^2+y^2-m y=0. The value of mm is

Options

  1. A
    1
  2. B
    2
  3. C
    4
  4. D
    3

Correct answer

C.
4

Step-by-step solution

Here h=0,k=2h=0, k=2 and r=2r=2. Therefore, the required equation of the circle is :
(x−0)2+(y−2)2=(2)2(x-0)^2+(y-2)^2=(2)^2
or x2+y2−4y+4=4x^2+y^2-4 y+4=4 or x2+y2−4y=0x^2+y^2-4 y=0
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