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BITSAT 2014
Exam
BITSAT
Year
2014
Subject
Mathematics
Chapter
Continuity and Differentiability

BITSAT 2014 · Mathematics · Continuity and Differentiability

Let f(x)=\ array c (x-1) (1)/(x-1) if x ≠ 1 0 if x=1 array . Then...

Let f(x)=\left\{(x−1)sin⁡1x−1 if x≠10 if x=1\begin{array}{c}(x-1) \sin\frac{1}{x-1} \text{ if } x \neq 1 \\ 0 \quad \text{ if } x=1\end{array}\right. Then which one of the following is true?

Options

  1. Aff is differentiable at x=0x=0 and x=1x=1
  2. Bff is differentiable at x=0x=0 but not at x=1x=1
  3. Cff is differentiable at x=1x=1 but not at x=0x=0
  4. Dff is neither differentiable at x=0x=0 nor at x=1x=1

Correct answer

B. ff is differentiable at x=0x=0 but not at x=1x=1

Step-by-step solution

We have; f(x)=\left\{(x−1)sin⁡(1x−1) if x≠10 if x=1\begin{array}{ll}(x-1) \sin\left(\frac{1}{x-1}\right) & \text{ if } x \neq 1 \\ 0 & \text{ if } x=1\end{array}\right.R f^{\prime}(1)=\lim _{h \rightarrow 0} \frac{f(1+h)-f(1)}{h}=\lim _{h \rightarrow 0} \frac{h \sin \frac{1}{h}-0}{h}=\lim _{h \rightarrow 0} \sin \frac{1}{h} which does not exist. ∴f\therefore f is not differentiable at x=1x=1 Also \left.f^{\prime}(0)=\sin \frac{1}{(x-1)}-\frac{x-1}{(x-1)^{2}} \cos \left(\frac{1}{x-1}\right)\right]_{x=0}=-\sin 1+\cos 1\therefore fisdifferentiableatis differentiable atx=0
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