BITSAT2012MathematicsContinuity and DifferentiabilityActual
If the function f(x)= cases A x-B, & x 1 3 x & , 1
Options
- A3,5
- B3,-5
- C0,3
- D0,5
Correct answer
B. 3,-5
Step-by-step solution
Since f ( x ) is continuous at x =2 f (2)= _ x 2⁺ f ( x ) 1= _ x 2⁺ ( ax + b ) 1=2 a + b Again f ( x ) is continuous at x =4 f (4)= _ x 4⁻ f ( x ) 7= _ x 4⁻ ( ax + b ) 7=4 a + b Solving (1) and (2), we get a=3, b=-5
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Options
- A3,5
- B3,-5
- C0,3
- D0,5
Correct answer
B. 3,-5
Step-by-step solution
Since f ( x ) is continuous at x =2 f (2)= _ x 2⁺ f ( x ) 1= _ x 2⁺ ( ax + b ) 1=2 a + b Again f ( x ) is continuous at x =4 f (4)= _ x 4⁻ f ( x ) 7= _ x 4⁻ ( ax + b ) 7=4 a + b Solving (1) and (2), we get a=3, b=-5