BITSAT 2011
- Exam
- BITSAT
- Year
- 2011
- Subject
- Mathematics
- Chapter
- Continuity and Differentiability
BITSAT 2011 · Mathematics · Continuity and Differentiability
The function f(x)=(x-1) | n x| is at x=1)
The function is at
Options
- Adiscontinuous
- Bcontinuous but not differentiable
- Cdifferentiable with (f^{\prime}(1)=0)
- Ddifferentiable with (\mathrmf^{\prime}(1) \neq 0)
Correct answer
C. differentiable with (f^{\prime}(1)=0)
Step-by-step solution
Continuous as well as differentiable, so (f^{\prime}(1)=0)