BITSAT 2010
- Exam
- BITSAT
- Year
- 2010
- Subject
- Mathematics
- Chapter
- Continuity and Differentiability
BITSAT 2010 · Mathematics · Continuity and Differentiability
The value of ( | array ccc 1 & 2 & 3 -4 & 3 & 6 2 & -7 & 9 array |)...
The value of (
\left|1−4223−7369\right|) isStep-by-step solution
$\begin{aligned}& \left|\begin{array}{ccc}1 & 2 & 3 \\ -4 & 3 & 6 \\ 2 & -7 & 9\end{array} \right|=1\left| \begin{array}{cc}3 & 6 \\ -7 & 9\end{array} \right|-2\left| \begin{array}{cc}-4 & 6 \\ 2 & 9\end{array} \right|+3 \\ & \left| \begin{array}{cc}-4 & 3 \\ 2 & -7\end{array} \right| \\ & \end{aligned})
=1(3×9−6(−7))−2(−4×9−2×6)+3((−4)(−7)−3×2)=(27+42)−2(−36−12)+3(28−6)=231$$)
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