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BITSAT 2016
Exam
BITSAT
Year
2016
Subject
Mathematics
Chapter
Determinants

BITSAT 2016 · Mathematics · Determinants

If the matrix [ array ccc 1 & 3 & λ+2 2 & 4 & 8 3 & 5 & 10 array ]...

If the matrix \left[13λ+22483510\begin{array}{ccc}1 & 3 & \lambda+2 \\ 2 & 4 & 8 \\ 3 & 5 & 10\end{array}$\right] is singular, then $\lambda=

Options

  1. A-2
  2. B4
  3. C2
  4. D-4

Correct answer

B. 4

Step-by-step solution

∣A∣=0|\mathrm{A}|=0 as the matrix A\mathrm{A} is singular \therefore|\mathrm{A}|=\left|13λ+22483510\begin{array}{ccc}1 & 3 & \lambda+2 \\ 2 & 4 & 8 \\ 3 & 5 & 10 \end{array}$\right|=0 Apply\mathrm{R}_{2} \rightarrow \mathrm{R}_{2}-2 \mathrm{R}_{1}andand\mathrm{R}_{3}→\rightarrow\mathrm{R}_{3}-33\mathrm{R}_{1}and expand. −2(4−3λ)+4(4−2λ)=0⇒8−2λ=0⇒λ=4-2(4-3 \lambda)+4(4-2 \lambda)=0 \Rightarrow 8-2 \lambda=0 \Rightarrow \lambda=4 For λ=4,\lambda=4, the second and the third column are proportional.$
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