BITSAT 2016
- Exam
- BITSAT
- Year
- 2016
- Subject
- Mathematics
- Chapter
- Determinants
BITSAT 2016 · Mathematics · Determinants
If [ ] denotes the greatest integer less than or equal to the real...
If [ ] denotes the greatest integer less than or equal to the real number under consideration and then the value of the determinant ![If [ ] denotes the greatest integer less than or equal to the real number under consideration and -1 ≤ x is](/api/proxy-image?url=https%3A%2F%2Ffirebasestorage.googleapis.com%2Fv0%2Fb%2Fquantrexacademy-app.firebasestorage.app%2Fo%2Fquestions%252Ffigs%252Fpyq%252Fbitsat%252FDgEyjvV-MrArf9uTrBueZOFNbrMce-IM0nBGrN4pi28.original.fullsize.png%3Falt%3Dmedia&clean=1&v=wm2)
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![If [ ] denotes the greatest integer less than or equal to the real number under consideration and -1 ≤ x is](/api/proxy-image?url=https%3A%2F%2Ffirebasestorage.googleapis.com%2Fv0%2Fb%2Fquantrexacademy-app.firebasestorage.app%2Fo%2Fquestions%252Ffigs%252Fpyq%252Fbitsat%252FDgEyjvV-MrArf9uTrBueZOFNbrMce-IM0nBGrN4pi28.original.fullsize.png%3Falt%3Dmedia&clean=1&v=wm2)
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Options
- A
- B
- C
- DNone of these
Correct answer
A.
Step-by-step solution
Since, \begin{array}{ll}\therefore \quad & {[\mathrm{x}]=-1} \\ & 0 \leq \mathrm{y}< 1 \quad \therefore[\mathrm{y}]=0 \\ & 1 \leq \mathrm{z}< 2 \quad \therefore[\mathrm{z}]=1 \\ \therefore \quad & \text{ Given determinant }=\left|\begin{array}{ccc}0 & 0 & 1 \\ -1 & 1 & 1 \\ -1 & 0 & 2\end{array}\right|=1=[\mathrm{z}]\end{array}