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BITSAT2019MathematicsProbabilityActual

Three numbers are chosen at random without replacement from 1 , 2 , 3 , … … , 8 . The probability that their minimum is 3 , given that their maximum is 6 , is

Options

  1. A3 8
  2. B1 5
  3. C1 4
  4. D2 5

Correct answer

B. 1 5

Step-by-step solution

Let A be the event that maximum is 6 . B be the event that minimum is 3 . P A = C 2 5 C 3 8 (number less than 6 is 5 ) P B = C 2 5 C 3 8 (number greater than 3 is 5 ) P A ∩ B = C 1 2 C 3 8 ∴ Required probability = P B / A = P A ∩ B P A = C 1 2 C 2 5 = 2 10 = 1 5

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