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BITSAT 2017
Exam
BITSAT
Year
2017
Subject
Mathematics
Chapter
Probability

BITSAT 2017 · Mathematics · Probability

If the papers of 4 students can be checked by any one of the 7...

If the papers of 44 students can be checked by any one of the 77 teachers, then the probability that all the 44 papers are checked by exactly 22 teachers, is equal to

Options

  1. A1249\dfrac{12}{49}
  2. B649\dfrac{6}{49}
  3. C949\dfrac{9}{49}
  4. D1549\dfrac{15}{49}

Correct answer

B. 649\dfrac{6}{49}

Step-by-step solution

Total ways in which papers can be checked is equal& 74{7}^{4}. Now, two teachers who have to check all the papers can be selected in C27C2 7 ways and papers can be checked by them is (24−2)\left({2}^{4} - 2\right) favourable ways.

Thus, required probability

=C27(24−2)74=649= \dfrac{C2 7 \left({2}^{4} - 2\right)}{74} = \dfrac{6}{49}

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