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BITSAT 2015
Exam
BITSAT
Year
2015
Subject
Mathematics
Chapter
Probability

BITSAT 2015 · Mathematics · Probability

A bag contains 3 red and 3 white balls. Two balls are drawn one by...

A bag contains 3 red and 3 white balls. Two balls are drawn one by one. The probability that they are of different colours is.

Options

  1. A3/103 / 10
  2. B2/52 / 5
  3. C3/53 / 5
  4. DNone of these

Correct answer

C. 3/53 / 5

Step-by-step solution

Let A≡\mathrm{A} \equiv event that drawn ball is red B≡\mathrm{B} \equiv event that drawn ball is white Then ABand\mathrm{AB} and\mathrm{BA}aretwodisjointcasesofthegivenevent.are two disjoint cases of the given event.\thereforeP(AB+BA)=P(AB)+P(BA)=P(A)P(BA)+P(B)P(AB)\begin{array}{l} \thereforeP(A B+B A)=P(A B)+P(B A) \\ =P(A) \quad P\left(\frac{B}{A}\right)+P(B) \quad P\left(\frac{A}{B}\right) \end{array}$=\frac{3}{6} \cdot \frac{3}{5}+\frac{3}{6} \cdot \frac{3}{5}=\frac{3}{5}
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