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BITSAT 2011
Exam
BITSAT
Year
2011
Subject
Mathematics
Chapter
Probability

BITSAT 2011 · Mathematics · Probability

A die is loaded such that the probability of throwing the number i...

A die is loaded such that the probability of throwing the number ii is proportional to its reciprocal. The probability that 3 appears in a single throw is-

Options

  1. A3/223 / 22
  2. B3/113 / 11
  3. C9/229 / 22
  4. DNone of these

Correct answer

D. None of these

Step-by-step solution

P(i)=ki⇒1=∑i=16P(i)=k∑i=161i=k4920⇒k=2049.P(3)=20147\begin{aligned}& \mathrm{P}(\mathrm{i})=\frac{\mathrm{k}}{\mathrm{i}} \Rightarrow \mathrm{1}=\sum_{\mathrm{i}=1}^6 \mathrm{P}(\mathrm{i})=\mathrm{k} \sum_{\mathrm{i}=1}^6 \frac{1}{\mathrm{i}}=\mathrm{k} \frac{49}{20}\\ & \Rightarrow \mathrm{k}=\frac{20}{49}. \mathrm{P}(3)=\frac{20}{147} \end{aligned}
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