BITSAT2010MathematicsProbabilityActual
The equation of the plane containing the line ( x - x ₁ = y - y ₁ ~m = z - z ₁ n ) is (a (x-x₁ )+b (y-y₁ )+c (z-z₁ )=0 ), then
Options
- A( ax ₁+ by ₁+ cz ₁=0 )
- B(a +b m+c n=0 )
- C( a = b m = c n )
- D( x ₁+ my ₁+ nz ₁=0 )
Correct answer
B. (a +b m+c n=0 )
Step-by-step solution
If the given plane contains the given line then the normal to the plane, must be perpendicular to the line and the condition for the same is (a +b m+c n=0 ).