Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
BITSAT2009MathematicsProbabilityActual

It is given that the events (A ) and (B ) are such that (P(A)= 1 4 , P(A B)= 1 2 ) and ( P(B A)= 2 3 ). Then (P(B) ) is

Options

  1. A( 1 6 )
  2. B( 1 3 )
  3. C( 2 3 )
  4. D( 1 2 )

Correct answer

B. ( 1 3 )

Step-by-step solution

(P(A)=1 / 4, P(A / B)= 1 2 , P(B / A)=2 / 3 ) By conditional probability, ( aligned & P(A B)=P(A) P(B / A)=P(B) P(A / B) & 1 4 2 3 =P(B) 1 2 P(B)= 1 3 aligned )

Practice Probability on Quantrex Academy →

More from Probability

The probability of getting 10 in a single throw of three fair dice is 2024In a binomial distribution, the mean is 4 and variance is 3 . Then, its mode is 2024The probability that certain electronic component fails when first used is 0.10 . If it does not fail immediately, the probability that it lasts for one year is 0.99 . The probabil 2024Given below is the distribution of a random variable X If = P (X 3) and = P (X 2) , then : = 2024A book contains 1000 pages. A page is chosen at random. The probability that the sum of the digits of the marked number on the page is equal to 9 , is 2024For two events A and B , if P ( A )= P ( A B )= 1 4 and P ( B A )= 1 2 , then which of the following is not true? 2024If A and B are mutually exclusive events and if P ( B )= 1 3 , P ( A B )= 13 21 , then P ( A ) is equal to 2023A coin is tossed twice. Then, the probability that atleast one tail occurs is 2023 Full Probability list All BITSAT PYQs