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BITSAT2009MathematicsProperties of TrianglesActual

The random variable ( X ) has the following probability distribution ( array |c|c|c|c|c|c| x & 0 & 1 & 2 & 3 & 4 P ( X = x ) & k & 3 k & 5 k & 2 k & k array ) Then the value of (P(X 2) ) is

Options

  1. A( 1 3 )
  2. B( 2 3 )
  3. C( 3 4 )
  4. D( 1 4 )

Correct answer

B. ( 2 3 )

Step-by-step solution

Since, ( P _ i ( X = x )=1 ) ( aligned & k +3 k +5 k +2 k + k =1 12 k =1 k = 1 12 & Now, P ( X 2)= P ( X =2)+ P ( X =3)+ P ( X =4) & =5 k +2 k + k =8 k =8 ( 1 12 )= 2 3 aligned )

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