Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
BITSAT 2009
Exam
BITSAT
Year
2009
Subject
Mathematics
Chapter
Properties of Triangles

BITSAT 2009 · Mathematics · Properties of Triangles

The random variable (X) has the following probability distribution...

The random variable (\mathrm{X}) has the following probability distribution <tableclass="qx−match−listqx−match−table"border="1"cellpadding="6"cellspacing="0"><tr><td>x</td><td>0</td><td>1</td><td>2</td><td>3</td><td>4</td></tr><tr><td>P(X=x)</td><td>k</td><td>3k</td><td>5k</td><td>2k</td><td>k</td></tr></table><table class="qx-match-list qx-match-table" border="1" cellpadding="6" cellspacing="0"><tr><td>x</td><td>0</td><td>1</td><td>2</td><td>3</td><td>4</td></tr><tr><td>P(X=x)</td><td>k</td><td>3 k</td><td>5 k</td><td>2 k</td><td>k</td></tr></table>) Then the value of (P(X \geq 2)) is

Options

  1. A(13\frac{1}{3})
  2. B(23\frac{2}{3})
  3. C(34\frac{3}{4})
  4. D(14\frac{1}{4})

Correct answer

B. (23\frac{2}{3})

Step-by-step solution

Since, ΣPi(\Sigma \mathrm{P}_{\mathrm{i}}(\mathrm{X}=\mathrm{x})=1))=1)∴k+3k+5k+2k+k=1∴12k=1∴k=112 Now, P(X≥2)=P(X=2)+P(X=3)+P(X=4)=5k+2k+k=8k=8(112)=23\begin{aligned}& \therefore \mathrm{k}+3 \mathrm{k}+5 \mathrm{k}+2 \mathrm{k}+\mathrm{k}=1 \therefore 12 \mathrm{k}=1 \therefore \mathrm{k}=\frac{1}{12}\\ & \text{ Now, } \mathrm{P}(\mathrm{X} \geq2)=\mathrm{P}(\mathrm{X}=2)+\mathrm{P}(\mathrm{X}=3)+\mathrm{P}(\mathrm{X}=4) \\ & =5 \mathrm{k}+2 \mathrm{k}+\mathrm{k}=8 \mathrm{k}=8\left(\frac{1}{12}\right)=\frac{2}{3} \end{aligned}$$
Practice Properties of Triangles on Quantrex Academy →

More from Properties of Triangles

If in a A B C, 2 b^2=a^2+c^2 , then ( 3B)/( B) is equal to BITSAT 2022Let ABC be an acute-angled triangle and let D be the mid-point of BC . If AB = AD , then… BITSAT 2019In a ABC, if A a = B b = C c , and the side a=2, then area of the triangle is BITSAT 2016In a A B C , the lengths of the two larger sides are 10 and 9 units, respectively. If the… BITSAT 2015In a triangle ABC, if a=2, B=60^ ^ ∘ and C=75^ ^ ∘ , then b equals BITSAT 2012In an equilateral triangle, the in radius, circumradius and one of the ex-radii are in… BITSAT 2011 Full Properties of Triangles list Properties of Triangles JEE Maths PYQsJEE Mathematics PYQs All BITSAT PYQs