The roots of the given equation (p-q) x^2+(q-r) x+(r-p)=0 are :

Step-by-step solution

Given equation is (p-q) x^2+(q-r) x+(r-p)=0 By using formula for finding the roots viz: -b b^2-4 a c 2 a , we get aligned & x= (r-q) (q-r)^2-4(r-p)(p-q) 2(p-q) & x= (r-q) (q+r-2 p) 2(p-q) = r-p p-q , 1 aligned