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BITSAT 2023Paper 1
Exam
BITSAT
Year
2023
Paper
Paper 1
Subject
Mathematics
Chapter
Quadratic Equation

BITSAT 2023 · Paper 1 · Mathematics · Quadratic Equation

If one root of the equation x^2+p x+12=0 is 4, while the equation...

If one root of the equation x2+px+12=0x^2+p x+12=0 is 4, while the equation x2+px+q=0x^2+p x+q=0. has equal roots, then the value of ' qq ' is

Options

  1. A4
  2. B12
  3. C3
  4. D494\frac{49}{4}

Correct answer

D. 494\frac{49}{4}

Step-by-step solution

4 is a root of x2+px+12=0x^2+p x+12=0
⇒16+4p+12=0⇒p=−7\Rightarrow 16+4 p+12=0 \Rightarrow p=-7
Now, the equation x2+px+q=0x^2+p x+q=0 has equal roots.
∴p2−4q=0⇒q=p24=494\therefore p^2-4 q=0 \Rightarrow q=\frac{p^2}{4}=\frac{49}{4}
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